Trent W. Buck via luv-talk wrote: Trent: If the battery has a nominal voltage of ~ 4volts ; 3.5kAH represents (3.5) . (4) kAVH = 14 kwatt.hours !; 3.5k mA H seems more likely.! You may not be alone though; it is my impression that 'units' and a foundational understanding, of what a measurement 'is' and what a measure ' is' are given little prominence outside of , courses like physics and engineering. Thus we have economists talking about, " a good set of numbers' and IT people with a poor idea of what the bytes at some; location are finally intended to represent; in a particular context, Beyond 'dimensional' balancing of equations ([M]^x,[L]^y,[T]^z must be the same on both sides !); I find it useful in unit conversions : eg [newtons] = [kilograms.m.sec^-2] to remember (for example); 1 kilogram = 2.2 lb implies 1= 2.2[ lb.kg^-1] and 1 m = 3.28 ft implies 1 = 3.28[ ft.m^-1] thus [newtons] = [kg.m.sec^-2].[2.2 lb.kg^-1].[ 3.28 ft.m^-1] = .(2.2).(3.28) [lb.ft.sec^-2] .............. (kg and m cancel) = .(7.21).[lb.ft.sec^-2] = 7.2 [1lbl] ( pronounced poundal] nb 1 lbf = 32 lbl; -obviously not much call for metric to imperial conversion these days; but the method is perfectly general ! regards Rohan McLeod