On 4 June 2015 at 16:27, Trent W. Buck <trentbuck@gmail.com> wrote:
Craig Sanders <cas@taz.net.au> writes:
[...] to be able to suspend to disk [...] you need at least as much swap as RAM.
AIUI in a situation like this, I'd need 256MiB (not 2GiB) of swap to suspend-to-disk.
$ free -m total used free shared buffers cached Mem: 1884 1178 706 269 0 966 -/+ buffers/cache: 211 1673
...but I guess the space saved is not worth the cost of being unable to suspend-to-disk when firefox is open.
Curious as to how you came to that conclusion? I found a couple of references to /sys/power/image_size as being the factor that deteremines how big the suspend-to-disk image will be. According to https://www.kernel.org/doc/Documentation/power/interface.txt it's set to 2/5 of availanble RAM by default, as is the case on my home media server where it's set to 2/5 of 16Gb i.e. 6641303552 bytes. You can change of course and apparently setting it to zero causes the kernel to create the smallest image possible. -- Colin Fee tfeccles@gmail.com